#ifndef CSUM_H #define CSUM_H #include #include #include "built_in.h" static inline unsigned short csum(unsigned short *buf, int nwords) { unsigned long sum; for (sum = 0; nwords > 0; nwords--) sum += *buf++; sum = (sum >> 16) + (sum & 0xffff); sum += (sum >> 16); return ~sum; } static inline uint16_t calc_csum(void *addr, size_t len, int ccsum __maybe_unused) { return csum(addr, len >> 1); } static inline uint16_t csum_expected(uint16_t sum, uint16_t computed_sum) { uint32_t shouldbe; shouldbe = sum; shouldbe += ntohs(computed_sum); shouldbe = (shouldbe & 0xFFFF) + (shouldbe >> 16); shouldbe = (shouldbe & 0xFFFF) + (shouldbe >> 16); return shouldbe; } /* Taken and modified from tcpdump, Copyright belongs to them! */ struct cksum_vec { const uint8_t *ptr; int len; }; #define ADDCARRY(x) \ do { if ((x) > 65535) \ (x) -= 65535; \ } while (0) #define REDUCE \ do { \ l_util.l = sum; \ sum = l_util.s[0] + l_util.s[1]; \ ADDCARRY(sum); \ } while (0) static inline uint16_t __in_cksum(const struct cksum_vec *vec, int veclen) { const uint16_t *w; int sum = 0, mlen = 0; int byte_swapped = 0; union { uint8_t c[2]; uint16_t s; } s_util; union { uint16_t s[2]; uint32_t l; } l_util; for (; veclen != 0; vec++, veclen--) { if (vec->len == 0) continue; w = (const uint16_t *) (void *) vec->ptr; if (mlen == -1) { s_util.c[1] = *(const uint8_t *) w; sum += s_util.s; w = (const uint16_t *) (void *) ((const uint8_t *) w + 1); mlen = vec->len - 1; } else mlen = vec->len; if ((1 & (unsigned long) w) && (mlen > 0)) { REDUCE; sum <<= 8; s_util.c[0] = *(const uint8_t *) w; w = (const uint16_t *) (void *) ((const uint8_t *) w + 1); mlen--; byte_swapped = 1; } while ((mlen -= 32) >= 0) { sum += w[0]; sum += w[1]; sum += w[2]; sum += w[3]; sum += w[4]; sum += w[5]; sum += w[6]; sum += w[7]; sum += w[8]; sum += w[9]; sum += w[10]; sum += w[11]; sum += w[12]; sum += w[13]; sum += w[14]; sum += w[15]; w += 16; } mlen += 32; while ((mlen -= 8) >= 0) { sum += w[0]; sum += w[1]; sum += w[2]; sum += w[3]; w += 4; } mlen += 8; if (mlen == 0 && byte_swapped == 0) continue; REDUCE; while ((mlen -= 2) >= 0) { sum += *w++; } if (byte_swapped) { REDUCE; sum <<= 8; byte_swapped = 0; if (mlen == -1) { s_util.c[1] = *(const uint8_t *) w; sum += s_util.s; mlen = 0; } else mlen = -1; } else if (mlen == -1) s_util.c[0] = *(const uint8_t *) w; } if (mlen == -1) { s_util.c[1] = 0; sum += s_util.s; } REDUCE; return (~sum & 0xffff); } static inline uint16_t p4_csum(const struct ip *ip, const uint8_t *data, uint16_t len, uint8_t next_proto) { struct cksum_vec vec[2]; struct pseudo_hdr { uint32_t src; uint32_t dst; uint8_t mbz; uint8_t proto; uint16_t len; } ph; memset(&ph, 0, sizeof(ph)); ph.len = htons(len); ph.mbz = 0; ph.proto = next_proto; ph.src = ip->ip_src.s_addr; ph.dst = ip->ip_dst.s_addr; vec[0].ptr = (const uint8_t *) (void *) &ph; vec[0].len = sizeof(ph); vec[1].ptr = data; vec[1].len = len; return __in_cksum(vec, 2); } #endif /* CSUM_H */ n value='4'>4space:mode:
authorThierry Reding <treding@nvidia.com>2016-03-04 16:50:50 +0100
committerThierry Reding <treding@nvidia.com>2016-04-29 16:47:30 +0200
commit13541cc3d42faef262cbae21331128c065d7dc5d (patch)
treef775908e9a52929477768d7dd751574f15e6f06b /Documentation
parent4000b00f3ca0be65ea947610f7eb8a09f6052756 (diff)
dt-bindings: pci: tegra: Update for per-lane PHYs
The XUSB pad controller allows PCIe lanes to be controlled individually, providing fine-grained control over their power state. Previous attempts at describing the XUSB pad controller in DT had erroneously assumed that all PCIe lanes were driven by the same PHY, and hence the PCI host controller would reference only a single PHY. Moving to a representation of per-lane PHYs requires that the operating system driver for the PCI host controller have access to the set of PHY devices that make up the connection of each root port in order to power up and down all of the lanes as necessary. Acked-by: Rob Herring <robh@kernel.org> Acked-by: Stephen Warren <swarren@nvidia.com> Signed-off-by: Thierry Reding <treding@nvidia.com>
Diffstat (limited to 'Documentation')